Every linear order isomorphic to its cube is isomorphic to its square VIII

Speaker: 

Garrett Ervin

Institution: 

UCI

Time: 

Monday, May 9, 2016 - 4:00pm to 5:30pm

Host: 

Location: 

RH 440R

We complete the proof of the main theorem by showing that if X^3 is isomorphic to X, then X^{\omega} has a parity-reversing automorphism. By our previous results this implies X^2 is isomorphic to X as well. The proof generalizes to show that for any n > 1, if X^n is isomorphic to X, then X^2 is isomorphic to X. Time permitting we will discuss related results, including the existence of an A and X such that A^2X is isomorphic to X, while AX is not.

Every linear order isomorphic to its cube is isomorphic to its square VII

Speaker: 

Garrett Ervin

Institution: 

UCI

Time: 

Monday, April 25, 2016 - 4:00pm to 5:30pm

Host: 

Location: 

RH 440R

We complete the proof of the main theorem by showing that if X^3 is isomorphic to X, then X^{\omega} has a parity-reversing automorphism. By our previous results this implies X^2 is isomorphic to X as well. The proof generalizes to show that for any n > 1, if X^n is isomorphic to X, then X^2 is isomorphic to X. Time permitting we will discuss related results, including the existence of an A and X such that A^2X is isomorphic to X, while AX is not.

 

Ordinal definable subsets of singular cardinals

Speaker: 

Dima Sinapova

Institution: 

University of Illinois Chicago

Time: 

Monday, May 2, 2016 - 4:00pm to 5:30pm

Host: 

Location: 

RH 440R

A remarkable theorem of Shelah states that if $\kappa$ is a singular strong limit cardinal of uncountable cofinality, then there is a subset $x$ of $\kappa$, such that $HOD_x$ contains the powerset of $\kappa$. We show that in general this is not  the case for countable cofinality. Using a version of diagonal supercompact extender Prikry forcing, we construct a generic extension in which there is a singular cardinal $\kappa$ with countable cofinality, such that $\kappa^+$ is supercompact in $HOD_x$ for all $x\subset\kappa$. This result was obtained during a SQuaRE meeting at AIM and is joint with Cummings, Friedman, Magidor, and Rinot.

Every linear order isomorphic to its cube is isomorphic to its square VI

Speaker: 

Garrett Ervin

Institution: 

UCI

Time: 

Monday, April 18, 2016 - 4:00pm to 5:30pm

Host: 

Location: 

RH 440R

Our eventual goal is to see that if X is any linear order that isomorphic to its cube, then X^{\omega} has a parity-reversing automorphism. Then by the results of last week, X will also be isomorphic to its square. This week, I will describe a method for building partial parity-reversing automorphisms on any A^{\omega}, and give structural conditions on A under which these partial automorphisms can be stitched together to get a full p.r.a. We will see in particular that if A is countable, then A^{\omega} has a p.r.a.

 

Every linear order isomorphic to its cube is isomorphic to its square V

Speaker: 

Garrett Ervin

Institution: 

UCI

Time: 

Monday, April 11, 2016 - 4:00pm to 5:30pm

Host: 

Location: 

RH 440R

Building on our characterization from last week of the orders X that are isomorphic to AX, we characterize those X that are isomorphic to AAX. We then write down a condition -- namely, the existence of a parity-reversing automorphism (p.r.a.) for the countable power of A -- under which the implication ``AAX = X implies AX = X" holds. In future talks, we will show that if X is isomorphic to its cube then the countable power of X has a p.r.a., and hence X is isomorphic to its square.

 

Every linear order isomorphic to its cube is isomorphic to its square IV

Speaker: 

Garrett Ervin

Institution: 

UCI

Time: 

Monday, April 4, 2016 - 4:00pm to 5:30pm

Host: 

Location: 

RH 440R

We continue toward a proof of the main theorem by characterizing, for a fixed linear order A, the collection of linear orders X such that AX is isomorphic to X, finishing the argument we started with the last time.

Every linear order isomorphic to its cube is isomorphic to its square

Speaker: 

Garrett Ervin

Institution: 

UCI

Time: 

Monday, February 29, 2016 - 4:00pm to 5:30pm

Host: 

Location: 

RH 440R

In 1950's Sierpinski asked whether there exists a linear order X isomorphic to its lexicographicaly ordered cube but not to its square. We will give some historical context and begin the proof that the answer is negative. More generally, if X is isomorphic to any of its finite powers X^n (n>1) then X is isomorphic to all of them.

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